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iVinArrow [24]
4 years ago
8

A ball is dropped from an upper floor, some unknown distance above your apartment. As you look out of your window, which is 1.5

m tall, you observe that it takes the ball 0.18 seconds to traverse the length of the window. Determine how high above the top of your window the ball was dropped. Ignore air resistance.
Physics
1 answer:
Fed [463]4 years ago
3 0

Answer:

2,829 meters

Explanation:

X= Vo t + 1/2 a t^2

Being

X=1,5 m, t=0,18 s and a=9,81 m/s2

Then

Vo=7, 45 m/s

Then we use

V=a.t

Being

V=Vo, and a=9,81 m/s2

t=0,75 seconds to my window

We use again

X= 1/2 a t^2

Being

t=0,75 s and a=9,81 m/s2

X=2,82 m

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Answer:

1.   3 m/s^{2}

2.   1.5 m/s^{2}

3.   3 seconds

4.   0 m/s^{2}

5.   2.2 seconds

Explanation:

(1)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

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a=\frac {v-u}{t}

Substituting u=0 since it’s at rest, v=30m/s and t=10 seconds

a = \frac {30-0}{10}=3 m/s^{2}

(2)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

Substituting u=10m/s, v=22m/s and t=8 seconds

a = \frac {22-10}{8}=1.5 m/s^{2}

(3)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

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= \frac {15-0}{5}=3s

(4)

When initial and final velocity are constant, there’s no acceleration as proven below

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

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a = \frac {20-20}{10}=0 m/s^{2}

(5)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

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Gallium is a solid metal at room temperature, but it will melt to a liquid in your hand. the melting point of gallium is 85.6 f.
Nimfa-mama [501]

Fahrenheit  =  85.6°F

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Celsius  =  (5/9) (85.6 - 32)

Celsius  =  (5/9) (53.6)

<em>Celsius  =  29.78°C</em>

Kelvin  =  Celsius + 273.15

Kelvin  =  29.78 + 273.15

<em>Kelvin  =  302.93K  </em>

5 0
2 years ago
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