Answer
correct answer is C
Head-to-tail method
Here head-to-tail method is employed to determine resultant of vectors.
Let horizontal component be 1 and let vertical component be 2
To add these two vectors. Move vector 2 until its tail touches the head of 1. The tail of resultant of these two vectors touch the tail of vector 1 and head of resultant vector will touch the head of vector 2.
Answer:
0.45
Explanation:
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
There are friction forces in two directions: centripetal and tangential. The centripetal acceleration is:
ac = v² / r
ac = (31 m/s)² / 333 m
ac = 2.89 m/s²
The total acceleration is:
a = √(ac² + at²)
a = √((2.89 m/s²)² + (3.32 m/s²)²)
a = 4.40 m/s²
Sum of forces:
∑F = ma
Nμ = ma
mgμ = ma
μ = a / g
μ = 4.40 m/s² / 9.8 m/s²
μ = 0.45
The cart comes to rest from 1.3 m/s in a matter of 0.30 s, so it undergoes an acceleration <em>a</em> of
<em>a</em> = (0 - 1.3 m/s) / (0.30 s)
<em>a</em> ≈ -4.33 m/s²
This acceleration is applied by a force of -65 N, i.e. a force of 65 N that opposes the cart's motion downhill. So the cart has a mass <em>m</em> such that
-65 N = <em>m</em> (-4.33 m/s²)
<em>m</em> = 15 kg
Answer:
d = 19.796m
Explanation:
Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.
So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.
Next, you look for a kinematic equation that has these parameters and the one you should choose is:

Now by substituting values in, we get
d = 19.796m
Answer:
Uniform
Explanation:
The Pascal's principle states that a change in pressure applied to an enclosed fluid is transmitted unchanged to all parts of the fluid and to the container's wall.
This implies that there is no change in magnitude of pressure at every point of the fluid and the walls of the container. Hence you can say that pressure is equal in all directions at any point of the fluid.