Explanation:
It is given that,
Speed, v₁ = 7.7 m/s
We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :
![\dfrac{1}{2}mv_1^2=\dfrac{1}{2}mv_2^2+mgh](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dmv_1%5E2%3D%5Cdfrac%7B1%7D%7B2%7Dmv_2%5E2%2Bmgh)
![v_2^2=v_1^2-2gh](https://tex.z-dn.net/?f=v_2%5E2%3Dv_1%5E2-2gh)
![v_2^2=(7.7)^2-2\times 10\times 1](https://tex.z-dn.net/?f=v_2%5E2%3D%287.7%29%5E2-2%5Ctimes%2010%5Ctimes%201)
![v_2=6.26\ m/s](https://tex.z-dn.net/?f=v_2%3D6.26%5C%20m%2Fs)
So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.
The answer is a rainforest I’m pretty sure
Answer:
As the capacitor is discharging, the current is increasing
Explanation:
Lets take
C= Capacitance
L=Inductance
V=Voltage
I= Current
The total energy E given as
![E=\dfrac{IL^2}{2}+\dfrac{CV^2}{2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BIL%5E2%7D%7B2%7D%2B%5Cdfrac%7BCV%5E2%7D%7B2%7D)
We know that total energy E is conserved so when electric energy 1/2 CV² decreases then magnetic energy 1/2 IL² will increases.
It means that when charge on the capacitor decreases then the current will increase.
As the capacitor is discharging, the current is increasing
It is an example of reflection of wave. C.
Answer:
Time taken = 8.25 second
Explanation:
Given:
Force = 4000 N
Force = ma
4,000 = (1100)(a)
Acceleration = 3.6363 m/s²
v = u + at
0 = 30 + (3.6363)t
Time taken = 8.25 second