Ask question

Ask question

All categories

3 years ago

9

A 160-m long ski lift carries skiers from a station at the foot of a slope to a second station 40 m above. What is the IMA of th

e lift?

2 answers:

e-lub [12.9K]3 years ago

8 0

Answer: ima = l/h which means 160/40 = 4

Explanation:

Dmitrij [34]3 years ago

4 0

Answer:

ima is l/h so 160/40 = 4

Explanation:

You might be interested in

How does the mass of an object affect its acceleration during free fall

ira [324]

The mass of an object has no effect whatsoever on the object's
acceleration during free-fall. If there is no air resistance to interfere
with the natural effects of gravity, then a feather and a battleship ...
dropped at the same time ... fall together, and hit the ground at the
same time.

8 0

3 years ago

Read 2 more answers

Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.

SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

$\rho(r) = ar^2 - br^3$

r is the radius of the spherical shell

dr is the thickness

volume of shell

$dV = 4 \pi r^2 dr$

mass of shell

$dM = \rho(r)dV$

$\rho = \rho_0 - br$

now,

$dM = (\rho_0 - br)(4 \pi r^2)dr$

integrating both side

$M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr$

$M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})$

$M = \pi R^3(\dfrac{\rho_0}{3}+\rho)$

we know,

$a = \dfrac{GM}{R^2}$

$a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}$

$a =\pi RG(\dfrac{\rho_0}{3}+\rho)$

$a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)$

a = 9.94 m/s²

7 0

3 years ago

. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency

morpeh [17]

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

$F_b = |F_1-F_2|$

Our values are given as,

$F_b = 5Hz$

$F_1 = 1050Hz$

Using the formula of the frequency I will have,

$F_b = |F_1-F_2|$

Replacing we have,

$5 = |1050-F_2|$

$F_2 = 1050 \pm 5$

$F_2 = 1045,1055 Hz$

The possible values are two: 1045Hz and 1055Hz

3 0

3 years ago

A person walks a distance of 3.0 km due

Nataly [62]

Answer:

Speed=1.6km/hr. I'm not sure about b

4 0

3 years ago

Which accounts for an increase in the temperature of a gas that is kept a constant volume

oksian1 [2.3K]

Answer:

An increase in pressure

Explanation:

The ideal gas law states that:

$pV=nRT$

where

p is the gas pressure

V is the volume

n is the number of moles

R is the gas constant

T is the temperature of the gas

in the equation, n and R are constant. For a gas kept at constant volume, V is constant as well. Therefore, from the formula we see that if the temperature (T) is increase, the pressure (p) must increase as well.

7 0

3 years ago