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3 years ago

Which of the following are ordered pairs for the equation y = 1/8x + 11?

Mathematics

2 answers:

Setler79 [48]3 years ago

7 0

The first one would be the answer

Mademuasel [1]3 years ago

5 0

Answer:

Again, A.

Step-by-step explanation:

Just graph the equation, but you can tell just by looking at it that (0,11) is the y-intercept meaning that it's one of the answer choices.

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PLEASE HELP, TWENTY POINTS PLUS BRAINLIEST

Sedbober [7]

The equation would be if y is the numbers in the sequence (like 3, 9, 27) and x is the is the number in the order (like 3 is 1, 9 is 2, 81 is 4) the the equation would be y = 3^x.

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2 years ago

Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K

zalisa [80]

<h2>Hello!</h2>

The answer is:

It will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

To calculate how long after they start they will be 3/4 miles apart, we need to write two equations.

So, writing the equations, we have:

Calculations for Ava:

We have the following information,

$v_{Ava}=6mph$

Then, writing the equation,

$x_{Ava}=x_{o}+v_{Ava}*t$

$x_{Ava}=x_{o}+v_{6mph}*t$

Calculations for Kelly:

We have the following information,

$v_{Kelly}=8mph$

We need to calculate when Kelly will be 3/4 miles apart of Ava, so, it's position will be the Ava's position plus 3/4 miles.

Then, writing the equation,

$x_{Ava}+0.75miles=x_{o}+v_{Kelly}*t$

$x_{Ava}+0.75miles=x_{o}+v_{8mph}*t$

Now, substituting Ava's speed into the second equation, we have:

$x_{o}+6mph*t+0.75miles=x_{o}+8mph*t$

$6mph*t+0.75miles=+8mph*t$

$8mph*t-6mph*t=0.75miles$

$2mph*t=0.75miles$

$t=\frac{0.75miles}{2mph}=0.375hours$

Hence, we have that it will took 0.375 hours for Ava and Kelly to be 3/4 miles apart.

Have a nice day!

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3 years ago

Read 2 more answers

David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu

vichka [17]

A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this: