Answer:
The solution is the point (18,0)
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system by substitution
substitute equation B in equation A
![\frac{1}{3}x-6=-\frac{1}{3}x+6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dx-6%3D-%5Cfrac%7B1%7D%7B3%7Dx%2B6)
solve for x
Adds (1/3)x both sides
![\frac{1}{3}x-6+\frac{1}{3}x=6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7Dx-6%2B%5Cfrac%7B1%7D%7B3%7Dx%3D6)
![\frac{2}{3}x-6=6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7Dx-6%3D6)
Adds 6 both sides
![\frac{2}{3}x=6+6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7Dx%3D6%2B6)
![\frac{2}{3}x=12](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7Dx%3D12)
![x=12(3)/2\\x=18](https://tex.z-dn.net/?f=x%3D12%283%29%2F2%5C%5Cx%3D18)
<em>Find the value of y</em>
substitute the value of x in equation A or equation B
![y=-\frac{1}{3}(18)+6=0](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7D%2818%29%2B6%3D0)
therefore
The solution is the point (18,0)
<h3>
Question: </h3><h3>
In the diagram below of Δ ABC, side BC is extended to point D, m∠A = x , m∠B = 2x+15, and m∠ACD = 5x+5 , what is m∠B ?</h3>
Answer: 3) m∠B = 25º
Step-by-step explanation:
Since m∠C is supplementary to m∠ACD
m∠C = 180º - m∠ACD
m∠C = 180º -(5·x + 5)
m∠C = 180º -5 -5·x
m∠C = 175º - 5·x
The sum of the angles of a triangle = 180º
m∠A + m∠B + m∠C = 180º
x + 2·x + 15º + 175º - 5·x = 180º
3·x - 5·x +190º = 180º
-2·x = 180º - 190º
-2·x = -10º
x = -10º/-2 = 5º
Now we can substitute this value of x in m∠B
m∠B = 2x+15
m∠B = 2·x + 15º = 2·5º + 15º = 10º + 15º = 25º
Answer: 3) m∠B = 25º
<h2><em>Spymore</em></h2>
Answer:
64, 65, 66
Step-by-step explanation:
16 x 4 = 64
13 x 5 = 65
6 x 11 = 66
^^
maybe C? sorry i’m not the best at this
The surface area of a rectangular prism is given by
... S = 2(LW +H(L+W))
For your dimensions, the surface area is
... S = 2(3·1 + 2(3+1)) = 2(3 + 8) = 22 . . . ft²