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marusya05 [52]
3 years ago
15

Can someone please help me with the first question?

Mathematics
2 answers:
Paraphin [41]3 years ago
6 0
Answer is A. 18
Because n + 18 =2n
krek1111 [17]3 years ago
3 0
#2 is 60°

All three angles in a triangle will always add up to 180°. You know one of them is 49°. To find the angle U, you can see that it falls on a flat line, which is going to equal 180°, so to find that angle you would subtract 109 from 180, giving you 71°. If two of the angles are stated, all you need is to subtract both from 180 to find what your last angle is.
So 180°-71°-49° = 60°


#4 I think is 75, but I don't feel like explaining it.

Hope this helps :))
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4 tables because the total amount of people is 24 and if you divide by 6 you get 4 so the greatest amount of tables is 4. There will be 6 adults and 1 kid at each table
5 0
4 years ago
217+37(3x−5)=−4 Drag and drop the statement that shows the solution to the equation into the box.
babunello [35]
Distribute on the left
217+111x-185=-4

Combine like terms
111x+32=-4

Sybtract 32 from both sides
111x=-36

Divide both sides by 111
x= -36/111
x=-12/37

Final answer: x=-12/37
6 0
3 years ago
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Triss [41]

1. 8(-18d-10) = -144d-80

2. -13+14(-18+10d) = -13-252+140d = -265+140d

3. 15(-7x-3) = -105x-45

The number are quite weird but we have to deal with them.

6 0
3 years ago
Read 2 more answers
Select all that apply.
Burka [1]

For this case we propose a rule of three to obtain the number that represents 25% of 37.

So, we have:

37 --------> 100%

x -----------> 25%

Where "x" is the number that represents 25% of 37.

x = \frac {25 * 37} {100}\\x = 9.25

Finally, we have that 25% of 37 is 9.25.

Answer:

25% of 37 is 9.25.

3 0
3 years ago
Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).
Katen [24]
We know that when A=(x_A,y_A) and B=(x_B,y_B) the midpoint of the line segment AB is given by:

M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)

Here A=(-2,5) and B=(6,-9) so:

M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)=\left(\dfrac{-2+6}{2},\dfrac{5+(-9)}{2}\right)=\\\\\\=\left(\dfrac{4}{2},\dfrac{5-9}{2}\right)=\left(2,\dfrac{-4}{2}\right)=\boxed{\left(2,-2\right)}

8 0
3 years ago
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