Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean = 
Standard deviation = 
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)
Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Answer:
7n + 5 − 9n = 8 − 2n − 3 = true
-2 n + 5 = 5 - 2 n = true
Step-by-step explanation:
Left-hand side:
Simplify the following:
7 n - 9 n + 5
Grouping like terms, 7 n - 9 n + 5 = 5 + (7 n - 9 n):
5 + (7 n - 9 n)
7 n - 9 n = -2 n:
Answer: -2 n + 5
____________________________
Right-hand side:
Simplify the following:
-2 n - 3 + 8
Grouping like terms, -2 n - 3 + 8 = (8 - 3) - 2 n:
(8 - 3) - 2 n
8 - 3 = 5:
Answer: 5 - 2 n
89,170,326
millions is the place value of 9
hope that helps :)
Answer:
Step-by-step explanation:
If you let y=2x, you can plug it into the other equation.
x+2x=-9
Then solve that equation.
3x=-9
x=-3
Then use y=2x to find y.
y=2(-3)=-6
y=-6
