To estimate the square root of a number that is not a perfect square, you would find the perfect squares that the number is between and you know the square roots of those, so the answer will be somewhere between them. The closer you are to the number below the number you are estimating for, the smaller the decimal (_.1, _.2, etc.) and then it is opposite as you get closer to the number above the number you are estimating for.
Jason hit 11 homeruns.
Step-by-step explanation:
Homeruns hit by Nathan = 19
Let,
Homeruns hit by Nathan = x
Homerun hit by Jason = y
According to given statement;
x = 2y - 3 Eqn 1
We know that Nathan hit 19 homeruns, therefore, putting x=19 in Eqn 1
Dividing both sides by 2;
Jason hit 11 homeruns.
Keywords: linear equations, addition
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Answer:
10. (4,-3) 11. (-3,-2)
Step-by-step explanation:
The left number is x and the right number is y.
So you just need to look for each coordinate and see if the line is touching it.
F(x) = f(-x)
<span>
If the point on the curve (x,y) is in the first quadrant,the opposite corner of the rectangle will be (-x,y). </span>
<span>So,
f(x) = 2 x y
= e^(-x^2)</span>
<span><span>f'(x) = d/<span>d x </span></span><span>[<span>e^<span>−<span>x^2</span></span></span>]
</span></span><span> = </span><span>e^−x^2</span><span>⋅</span><span>d/dx [−x^2]</span><span> =<span>(−<span><span>d/<span>d x </span></span><span>[<span>x^2</span>]</span></span>)</span><span>e^<span>−<span>x^2</span></span></span></span><span> =−2 x <span>e^<span>−<span>x^<span>2
= x (-2 e^-x)</span></span></span></span></span>
<span>f'(x) = 0
where x = 0 </span>
<span>So, x = 0
we only want the positive, real root here </span>
f(0) = e^(-0)
= 1
