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AleksAgata [21]
4 years ago
5

Determining a Number of Solutions

Mathematics
2 answers:
MatroZZZ [7]4 years ago
6 0

Answer:

No Solution

Step-by-step explanation:

<u>For one solution;</u>

it will be consistent and independent ( example, x = 1 and y = 2)

<u>For no solution;</u>

it will be inconsistent and independent ( example, 0 = 2)

<u>For many solution;</u>

it will be consistent and dependent ( example, 1 = 1,  2 = 2,  y = y,  x = x)

Given;

        3x - 2y = 3 -------------- equation (1)

        6x - 4y = 1 --------------- equation (2)

6:     18x - 12y = 18 -------------equation (3)

3:     18x - 12y = 3 --------------- equation (4),     <em>  subtract (4) from (3)</em>

      --------------------------------------------

        0 - 0      =  15

     -----------------------------------------------

       0 = 15

The solution is inconsistent and independent, because zero (0) cannot be equal to 15

Thus, the system has no solution

Zina [86]4 years ago
4 0

Answer:

ONE SOLUTION

3x-5y=8; 5x-3y=2

3x+2y=8; 4x+3y=1

NO SOLUTION

3x-4y=2; 6x-8y=1

3x-2y=3; 6x-4y=1

INFINITELY MANY SOLUTIONS

3x-6y=3; 2x-4y=2

Step-by-step explanation:

i got this right on edge

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