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3 years ago

What is the value of x????

Mathematics

1 answer:

AlekseyPX3 years ago

8 0

In a 45 · 45 · 90 triangle, the hypotenuse is √2 · legs, because a 45 · 45 · 90 triangle is isosceles, so the legs are the same length. So, we have 3√2 · √2 = 6, so the hypotenuse is 6.

x=6

You might be interested in

Which function has zeros at x=-2 and x=5?

Licemer1 [7]

Answer:

$x^{2} - 3x - 10$

Step-by-step explanation:

To start, lets form our polynomial factors from our zeroes.

x = -2

x + 2 = 0

x = 5

x - 5 = 0

Now lets put these into factored form by moving them into parenthesis and multiplying them with each other!

(x+2)(x-5)

We can start moving them out! I am going to use FOIL, but you could also use distributive or any other method/property.

x · x = x²

x · -5 = -5x

x · 2 = 2x

2 · 5 = 10

Now lets put our terms into our polynomial function, based on the order of the powers.

$x^{2} - 3x - 10$

We are done! Hope this helps!

7 0

3 years ago

Hi! Please explain how you got the answer, thanks! :))

disa [49]

Answer:

2000

Step-by-step explanation:

1996: 30+5 5×6=30

2000: 60+10 10×6=60

5 0

3 years ago

A rectangles side is 7.6 cm. the bottom of the rectangle is 11cm. what is the area?

DaniilM [7]

Answer:

83.6 cm

Step-by-step explanation:

Area = width x length

so 7.6 x 11

which is 83.6

Therefore, the area of the rectangle is 83.6 cm

hope this helps, give brainliest?

5 0

3 years ago

Read 2 more answers

After going shopping we had only 10% of our money left. We spent $180 how much money did we have at first

aivan3 [116]

Answer:18

Step-by-step explanation:

you have $18 dollars left

3 0

4 years ago

Read 2 more answers

Find the simplified product:<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2x%5E%7B3%7D%20%7D-%5Csqrt%7B18x%5E%7B5%7D%20%7D" id="Te

mash [69]

Correct Question: Find the simplified product: $\sqrt{2x^3}*\sqrt{18x^5}$

Answer:

$6x^4$

Step-by-step explanation:

Based on the rules of radicals, since $\sqrt{2x^3}$ and $\sqrt{18x^5}$ has the same index (square root), therefore:

$\sqrt{2x^3}*\sqrt{18x^5} = \sqrt{2x^3 * 18x^5}$

To simplify this, multiply their bases together, and add their exponents.

$= \sqrt{2*18x^{3+5}$

$= \sqrt{36x^{8}$

Simplify further

$= \sqrt{36}*\sqrt{x^8}$

$= \sqrt{6*6}*\sqrt{x^4*x^4}$

$= 6x^4$

7 0

3 years ago