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Ghella [55]
2 years ago
12

Challenge A large university accepts 50% of the students who apply. Of the students the

Mathematics
2 answers:
Monica [59]2 years ago
7 0

Answer:

Step-by-step explanation:

20,000 students 50% are accepted so that is 10,000 students of that 10,000 only 25% enroll which is 2,500.

julia-pushkina [17]2 years ago
7 0

Answer:

2,500 students

Step-by-step explanation:

50% of 20,000 is the amount of students that were accepted. That makes 10,000 students accepted. 25% of 10,000 is the amount enrolled. 25% is 1/4. So 1/4 of 10,000 is 2,500. So 2,500 students enrolled in that university.

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I need this for a geometry assignment........please help
anastassius [24]

All three are similar

In ∆SUT and ∆VWX

  • Two sides are similar and one angle is similar

So by SSA they are similar

In ∆PRQ and rest two

All angles are.

  • 80,80,20°

So

They are similar by AAA congruence

6 0
2 years ago
What is the difference between 5 hundreds and 3 tens?​
Umnica [9.8K]

Answer:

5 tens and 3 hundreds = 50 + 300 = 350. That is basically asking what number goes 5-3-2. This is because 5 hundreds means 5 in the hundreds place, or 500. 3 tens is just saying 3 in the tens place, or 30.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP 100 POINTS TO WHO HELPS ME
Misha Larkins [42]

Answer:

1. 13.65, 136.5, 1365    

2. 57.14, 5.714, .5714

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad 
C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}
\\\\\\
AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\
-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad 
D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}
\\\\\\
BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}
\\\\\\
BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]
\\\\\\
4[15]\implies 60

7 0
3 years ago
Read 2 more answers
What is the area of the square?
Vsevolod [243]
C. 84
12 x 8 is the area of the whole thing but you subtract 12 because of the missing 6x2 part of the square
4 0
3 years ago
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