9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
6
Step-by-step explanation:
75−3.5y−4y=4y+6
Step 1: Simplify both sides of the equation.
75−3.5y−4y=4y+6
75+−3.5y+−4y=4y+6
(−3.5y+−4y)+(75)=4y+6(Combine Like Terms)
−7.5y+75=4y+6
−7.5y+75=4y+6
Step 2: Subtract 4y from both sides.
−7.5y+75−4y=4y+6−4y
−11.5y+75=6
Step 3: Subtract 75 from both sides.
−11.5y+75−75=6−75
−11.5y=−69
Step 4: Divide both sides by -11.5.
−11.5y
−11.5
=
−69
−11.5
y=6
Hope this helps!
Answer:
x=6
Step-by-step explanation:
To solve this problem,
firstly make x to stand alone
subtract 6 from both sides of the equation
x+6-6=12-6
x= 6
Answer:
The percent error is -2.1352% of Jocelyn's estimate.
There is 17 Ounces left! Or 2.12500 cups.