Question

Az+17=−4z−b Solve for Z *this is a linear equation btw

Answer 1

we have

$Az+17=-4z-b$

Adds the term $4z$ both sides

$Az+17+4z=-4z-b+4z$

$Az+17+4z=-b$

Subtract the term $17$ both sides

$Az+17+4z-17=-b-17$

$Az+4z=-b-17$

$z(A+4)=-(b+17)$

Divide both sides by $(A+4)$

$z=-(b+17)/(A+4)$

therefore

the answer is

$z=-(b+17)/(A+4)$

Answer 2

Z=-b-17/a+4


Move all z-terms on one side of the equation, and move all constant terms to the other side of the equation.

Using the distributive property, group like terms together on both sides of the equation.

To isolate z, divide both sides by the coefficient of z