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2 years ago

63/4 as a mixed number

Mathematics

1 answer:

wel2 years ago

6 0

To find the answer, all you've got to do is divide 63 by 4. This will result in the mixed number: 15 3/4

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betty closes the nozzle and fills it completely with a liquid. She then opens the nozzle. If the liquid drips at the rate of 14

natta225 [31]

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

$r = 3$ -- radius

$h = 7$ --- height

$Rate = 14in^3/min$

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

$V = \frac{1}{3} \pi r^2h$

This gives:

$V = \frac{1}{3} * 3.14 * 3^2 * 7$

$V = \frac{1}{3} * 197.82$

$V = 65.94in^3$

To calculate the time, we make use of the following rate formula.

$Rate = \frac{Volume}{Time}$

Make Time the subject

$Time= \frac{Volume}{Rate }$

This gives:

$Time= \frac{65.94in^3}{14in^3/min}$

$Time= \frac{65.94in^3}{14in^3}min$

Cancel out the units

$Time= \frac{65.94}{14} min$

$Time= 4.71 min\\$

3 0

2 years ago

Simplify 2 to the 5 power to the fourth power over 3 to the second power

melisa1 [442]

I'm assuming you mean 2^(5)(4/3)(2).
So multiplying all of the powers together yields 2^(40/3)

4 0

2 years ago

The first U.S. census was conducted in 1790. At that time, the population was 3.93 million. Since then, the U.S. population has

Nikolay [14]

Answer:

It's actually A, because the US population got doubled ever year

4 0

2 years ago

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic

Free_Kalibri [48]

The equation for the situation is $y=200(\frac{2}{3})^{x}$

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is $y=a(b)^{x}$ , where

a is the initial value
b is the growth/decay factor
If b > 1, then it is a growth factor
If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is $\frac{2}{3}$

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is $y=a(b)^{x}$ , where y represent the

population in x years

∵ a = 200

∵ b = $\frac{2}{3}$

∴ $y=200(\frac{2}{3})^{x}$

The equation for the situation is $y=200(\frac{2}{3})^{x}$

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ $5=200(\frac{2}{3})^{x}$

- Divide both sides by 200

∴ $0.025=(\frac{2}{3})^{x}$

- Insert ㏒ for both sides

∴ $log(0.025)=log(\frac{2}{3})^{x}$

∴ $log(0.025)=xlog(\frac{2}{3})$

- Divide both sides by $log(\frac{2}{3})$

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation in brainly.com/question/10666510

#LearnwithBrainly

8 0

3 years ago

Let f(x)=2x-1 and g(x)=x^2 -3. Find (f o g)(-3)

anzhelika [568]

(f o g)(-3) = (f(g(-3))
Because g is on the inside, we carry out g first.

g(x) = x^2 - 3
Substitute -3 in for x.
g(-3) = (-3)^2 - 3 = 9 - 3 = 6
g(-3) = 6

Next, carry out f on the result of g(-3)
f(6) = 2(6) - 1
= 12 - 1
= 11
So the answer is 11.

6 0

2 years ago