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REY [17]
3 years ago
7

Brandon is shopping at Old Navy during a sale. All shorts are $16 each and all t-shirts are $10 each.He has $100 to spend and wo

uld like to purchase at least 2 pairs of shorts.
a) Write a system of linear inequalities to represent
this situation, then graph.
b)Using your graph, give two possible combinations
of shorts and Brandon can buy.

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0
Let
x = the number of shorts bought
y =  the number of t-shirts bought

A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10                 (1)

Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2                               (2)

Graph the equations y = -1.6x + 10 and  x = 2.
The shaded region satisfies both inequalities.

Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.

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The circumference of circle B is 48. The circumference of circle A is 12. How many times greater is the area of circle B to the
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Circle 1: 48=2(pi)(radius)
              24/pi = radius

Circle 2: 12 = 2(pi)(radius)
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Area = (pi)(radius)^2

Circle 1: A = (pi) (24/pi)^2
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3 years ago
For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form
jek_recluse [69]

Answer:

\displaystyle \cos(A + B) =\frac{969}{1769}

Step-by-step explanation:

We are given that:

\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

o=\sqrt{29^2-20^2}=21

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

h=\sqrt{11^2+60^2}=61

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)

Simplify:

\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}

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3 years ago
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