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yarga [219]
3 years ago
9

I made a binary sentence if you answer you get 75 points heres the code: 01101001 01100110 00100000 01111001 01101111 01110101 0

0100000 01100001 01110010 01100101 00100000 01110010 01100101 01100001 01100100 01101001 01101110 01100111 00100000 01110100 01101000 01101001 01110011 00100000 01001001 00100111 01101101 00100000 01110011 01110101 01110000 01110010 01101001 01110011 01100101 01100100 00100000 01111001 01101111 01110101 00100000 01100011 01100001 01101110 00100000 01110100 01110010 01100001 01101110 01110011 01101100 01100001 01110100 01100101 00100000 01110100 01101000 01101001 01110011 00100000 01110111 01100101 01101100 01101100
Computers and Technology
2 answers:
gavmur [86]3 years ago
8 0

if you are reading this I'm suprised you can translate this well this is easy

butalik [34]3 years ago
6 0

01001001 00100000 01100001 01100011 01110100 01110101 01100001 01101100 01101100 01111001 00100000 01110101 01110011 01100101 01100100 00100000 01100001 00100000 01000010 01101001 01101110 01100001 01110010 01111001 00100000 01100011 01101111 01100100 01100101 00100000 01000011 01101111 01101110 01110110 01100101 01110010 01110100 01100101 01110010 00100000 01101100 01101101 01100001 01101111

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four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
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3 years ago
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