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amm1812
3 years ago
10

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4pi units. The base of cylinder B has an

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

d) 9/4

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given circumference of cylinder A = π r² = 4π units

Given circumference of cylinder B = π r² = 9π units

The  dimensions of cylinder A are multiplied by \frac{9}{4}

   circumference of cylinder A = π r² = 4π(\frac{9}{4}) units     = 9 π units  

circumference cylinder A= 4π(\frac{9}{4}) units = 9 π units = circumference of cylinder B

<u><em>Final answer</em></u>:-

<em>The dimensions of cylinder A are multiplied by 9/4  produce the corresponding dimensions of cylinder B</em>

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\bold{ANSWER:}
28

\bold{SOLUTION:}

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3 years ago
a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or
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Answer:

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8 0
3 years ago
Find the equation of the form y=ax²+bx+c whose graph passes through the points (1,6), (3, 20), and (−2,15).
Korolek [52]

Answer:

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

Step-by-step explanation:

given ,

equation y=ax²+bx+c

passing through points (1,6), (3, 20), and (−2,15).

then these points will satisfy the equation

at (1,6)

y  = a x²+b x+c

6 = a(1)² + b (1) + c

a + b + c = 6------(1)

at (3 , 20)

y  = a x²+b x+c

20 = a(3)² + b (3) + c

9 a + 3 b + c = 20------(2)

at (−2,15)

y  = a x²+b x+c

15 = a(-2)² + b (-2) + c

4 a -2 b + c = 15------(3)

solving equation (1),(2) and (3)

a = 6 - b - c

9 (6 - b - c)+ 3 b + c = 20

6 b + 7 c = 34-------(4)

4 (6 - b - c) -2 b + c = 15

2 b + c = 3----------(5)

on solving equation (4) and (5)

c = \dfrac{25}{4}

b = \dfrac{-13}{8}

a = \dfrac{11}{8}

6 0
3 years ago
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