The measure of ∠1 is also <span>93° because vertically opposite angles are equal.</span>
A is the correct choose.could you make me brainlets answer please
Condition (A) P(B/A) = y is true.
<h3>
What is probability?</h3>
- Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
To find the true condition:
If two events are independent, then:
Use formulas for conditional probabilities:
- Pr(A/B) = Pr(A∩B) / Pr(B)
- Pr(B/A) = Pr(B∩A) / Pr(A)
For independent events these formulas will be:
- Pr(A/B) = Pr(A∩B) / Pr(B) = Pr(A) . Pr(B) / Pr(B) = Pr(A)
- Pr(B/A) = Pr(B∩A) / Pr(A) = Pr(B) . Pr(A) / Pr(A) = Pr(B)
Now in your case, Pr(A) = x and Pr(B) = y.
- Pr(A/B) = x, Pr(B/A) = y, Pr(A∩B) = x.y
Therefore, condition (A) P(B/A) = y is true.
Know more about probability here:
brainly.com/question/25870256
#SPJ4
The complete question is given below:
The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditions must be true?
a. P(B|A) = y
b. P(A|B) = y
c. P(B|A) = x
d. P(A and B) = x + y
e. P(A and B) = x/y
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
