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3 years ago

Solve for x. Enter your answer in the box. x =____°

Mathematics

2 answers:

irga5000 [103]3 years ago

7 0

The sum of all interior angles is (n-2)x180 while n=number of sides. So (6-2)x180=720. The angles you have add up to 588. All you need to do now is 720-588. x=132

Vlad1618 [11]3 years ago

6 0

we know that

The sum of all interior angles in the polygon is equal to the formula

$(n-2)*180\°$

where

n is the number of sides of the polygon

In this problem we have

$n=6$

substitute the value in the formula

$(6-2)*180\°=720\°$

<u>Find the value of x</u>

$720\°=x\°+108\°+113\°+132\°+75\°+160\°\\720\°=x\°+588\°\\x\°=720\°-588\°\\x=132\°$

therefore

<u>the answer is</u>

the measure of x is $132\°$

You might be interested in

(a) Use the fundamental theorem of algebra to determine the number of roots for 2x^2 + 4x + 7

zysi [14]

Answer:

Step-by-step explanation:

A 2nd order polynomial such as this one will have 2 roots; a 3rd order polynomial 3 roots, and so on.

The quadratic formula is one of the faster ways (in this situation, at least) in which to find the roots. From 2x^2 + 4x + 7 we get a = 2, b = 4 and c = 7.

Then the discriminant is b^2 - 4ac, or, here, 4^2 - 4(2)(7), or -40. Because the discriminant is negative, we know that the roots will be complex and unequal.

Using the quadratic formula:

-4 ±√[-40] -4 ± 2i√10

x = ------------------ = ------------------

4 4

-2 ± i√10

Thus, the roots are x = ------------------

4 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

2 years ago

Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu

goldenfox [79]

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

49.2 + 19.25 + 14.7 = 83.15

4 0

3 years ago

Three-quarters the product of two numbers x and y

serg [7]

Answer:

xy=3/4

Step-by-step explanation:

since it says the "product"

it is x(y)

3/4 goes after the = sign

4 0

2 years ago

The Mongolian Giant Sunflower produces seeds that are over 1 inch long, grow up to 18 feet tall, and flowers that are 1 ½ feet w

m_a_m_a [10]

Answer:

A sexually using seeds

Step-by-step explanation:

hope this helps :)

4 0

2 years ago