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2 years ago

Use the distributive property to simplify 0.75(3.5a-6b)

Mathematics

1 answer:

Studentka2010 [4]2 years ago

3 0

(0.75 * 3.5a) + (0.75 * -6b) = 2.63a -4.5b

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pyramid

Step-by-step explanation:

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2 years ago

(I think I know it just checking) Which function has a period equal to half the period of the function in y=5cos(3/5x-pi)+4.. th

eduard

Answer:

A is your answer

Step-by-step explanation:

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%28x%20-%201%29%20%5Cdiv%203%20%29%20-%202%20%5Cleqslant%20%28%285%20-%202x%29%20%5Cdiv%206

sergejj [24]

Answer:

x ≤ $\frac{19}{4}$

Step-by-step explanation:

Given

$\frac{x-1}{3}$ - 2 ≤ $\frac{5-2x}{6}$

Multiply through by 6 to clear the fractions

2(x - 1) - 12 ≤ 5 - 2x ← distribute and simplify left side

2x - 2 - 12 ≤ 5 - 2x

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4x - 14 ≤ 5 ( add 14 to both sides )

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x ≤ $\frac{19}{4}$

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2 years ago

Katie is going to a carnival and received $50 from her mother to spend. At the carnival, entry costs $12.00 and ride tickets cos

nlexa [21]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but I believe that you want to know the number of rides that Katie can take.

Based on the information in the question, we can form an equation. Let the number of rides that Katie can take be represented by x. Therefore,

12 + (1.25 × x) = 50

12 + 1.25x = 50

1.25x = 50 - 12

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x = 38/1.25

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Therefore, Katie can take at most 30 rides.

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2 years ago

Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo

pav-90 [236]

Answer:

Probability distribution vector = $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$

Step-By-Step Explanation

If $P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)$ is the transition matrix for a Markov chain with two states.

$x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)$ be the initial state vector for the population.

$X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)$

$X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)$

In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

This is called the steady-state (or limiting,) distribution vector.

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2 years ago