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Arisa [49]
2 years ago
5

. solve it I will mark u as brilliant​

Mathematics
1 answer:
Mkey [24]2 years ago
5 0

Answer:

5/100 , 7/2 ,4/5 321/100,  35/100, 607/1000, 3/2, 52/1

Step-by-step explanation:

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Evaluate b^2 for b= -4
tekilochka [14]

Answer:

16

Step-by-step explanation:

b^2

Let b= -4

(-4)^2

16

5 0
3 years ago
Read 2 more answers
An arithmetic sequence is defined by the general term tn = -5 + (n - 1)78, where n ∈N and n ≥ 1. What is the recursive formula o
GrogVix [38]

\text{The general term of an arithmetic sequence:}\ a_n=a_1+(n-1)d\\\\a_n-n-th\ term\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ t_n=-5+(n-1)78.\ \text{Therefore}\ t_1=-5\ \text{and}\ d=78\\\\\text{The recursive formula of the sequence:}\\\\\left\{\begin{array}{ccc}t_1=-5\\t_n=t_{n-1}+78\end{array}\right

5 0
3 years ago
140 fluid ounces increased by 45%
Leokris [45]
First divided 140 by 100 to find out how much 1 percent is
140 ÷ 100 = 1.4

multiply 1.4 by 45 to find 45 %; 1.4 x 45 = 63

then add 63, which is 45%, to 140, which is 100%, and you get 203, which is 140 + 45%, or 145%

please mark brainliest if this helped you. I hope it did!

4 0
3 years ago
Solve x(x-1) (X-5) <=O​
lara [203]

Answer:

x <= 0 or  1 = < x <= 5.

Step-by-step explanation:

First we find the critical points:

x(x - 1)(x - 5) = 0

gives x = 0, x = 1 and x = 5.

Construct a Table of values:

               <u>  x < 0 </u>  <u>x = 0 </u> 0<u>< x < 1</u>  <u>1 =< x <= 5</u>     <u>x = 5</u>

x                  <0        0          >0             <0           0

x - 1             <0       -1           >0              <0           0

x - 5            < 0       0          > 0             <0           0

x(x-1)(x-5)    < 0      0          >0              <0          0 

So the answers are x =< 0 or  1 =< x <= 5.

8 0
3 years ago
What are the coordinates of the vertex of the parabola described by the equation below? y = -7(x - 4)2 - 5
pochemuha
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)


7 0
3 years ago
Read 2 more answers
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