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Anna [14]
3 years ago
9

Which proportionality does Kepler’s third law describe?

Physics
2 answers:
stepladder [879]3 years ago
8 0

The correct answer to the question is T^2\ \alpha\ d^3.

EXPLANATION:

As per Kepler's third law on planetary motion, the square of time period of rotation of a planet around sun is directly proportional to the cube of semi major axis.This law is also called as harmonic law.

Let us consider a planet which is revolving around sun in an elliptical orbit.

Let R is the semi major axis of this elliptical orbit and T is the time period rotation of the planet around the sun.

As per Kepler's law, time period and semi major axis are related as -

                                T^2\ \alpha\ R^3  

beks73 [17]3 years ago
5 0

The correct answer is: D

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The cause of a magnetic force are small electrical currents or moving charges: Tiny circular currents at the atomic level are responsible in a permanent magnet for it to exert a magnetic force.

Explanation:

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A substance sample has a Mass of 45.0 g, and the Data Safety
marishachu [46]

The volume of the sample is 48.39 cm³.

<h3 /><h3>What is volume?</h3>

The term volume refers to the amount of three-dimensional space taken up by an item or a closed surface

To calculate the volume of the sample, we use the formula below

Formula:

  • D = m/v
  • v = m/D................ Equation 1

Where:

  • m = Mass of the smaple
  • D = Density of the sample
  • v = Volume of the sample.

From the question,

Given:

  • m = 45 g
  • D = 0.93 g/cm³

Substitute these values into equation 1

  • v = 45/0.93
  • v = 48.39 cm³

Hence, the volume of the sample is 48.39 cm³.

Learn more about volume here:brainly.com/question/27710307

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2 years ago
Some snakes have special sense organs that allow them to see the heat emitted from warm blooded animals what kind of an electrom
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The heat emitted from anything is carried in the form of infrared waves. (C)

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Movement of a stationary object
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3 years ago
Using Excel, or some other graphing software, plot the values of y as a function of x. (You will not submit this spreadsheet. Ho
Evgesh-ka [11]

Answer:

a) > x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept)            x  

      1.10         0.98  

b) y = 0.98 x +1.10

And if we compare this with the general model y = mx +b

We see that the slope is m= 0.98 and the intercept b = 1.10

Explanation:

Part a

For this case we have the following data:

x: 1,2,3,4,5

y: 1.9,3.5,3.7,5.1, 6

For this case we can use the following R code:

> x<-c(1,2,3,4,5)

> y<-c(1.9,3.5,3.7,5.1,6)

> linearmodel<-lm(y~x)

And the output is given by:

> linearmodel

Call:

lm(formula = y ~ x)

Coefficients:

(Intercept)            x  

      1.10         0.98  

Part b

For this case we have the following trend equation given:

y = 0.98 x +1.10

And if we compare this with the general model y = mx +b

We see that the slope is m= 0.98 and the intercept b = 1.10

7 0
3 years ago
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