Answer:
Explanation:
We can solve this problem using the principle of conservation of energy.
Starting point. For higher up the ramp
Em₀ = U = m g h
where h is the height of the ramp h = 3.00 m
Final point. For low
Em_{f} = K = ½ m v²
as there is no friction the mechanical energy is conserved
Em₀ = 
m g h = ½ m v²
v = √ (2g h)
let's calculate
v = √(2 9.8 3.00)
v = 7.668 m / s
Answer:
a = 2.72 ms⁻²
32.83 s
Explanation:
By using the kinematic equations you get,
v² = u² +2as and v = u + at where all terms in usual meaning
Using 1st equation,
89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²
By 2nd equation,
89.3 = 0 + 2.72×t ⇒ t = 32.83 s
Answer:
34 m/s
Explanation:
m = Mass of glider with person = 680 kg
v = Velocity of glider with person = 34 m/s
= Mass of glider without person = 680-60 kg
= Gliders speed just after the skydiver lets go
= Mass of person = 60 kg
= Velcotiy of person = 34 m/s
As the linear momentum of the system is conserved
The gliders speed just after the skydiver lets go is 34 m/s
Answer:
They would keep on moving but unless being acted upon or stop slowly because of the friction
Explanation:
I think it’s false bc A volcano is not in the interior of the earth
