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1 answer:
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Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α = /r
=2.513/0.287
=8.756 rad/s²