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andrey2020 [161]
3 years ago
15

Determine the maximum height and range of a projectile fired at a height of 6 feet above the ground with an initial velocity of

100 feet per second at an angle of 40 degrees above the horizontal.Maximum heightRange Question 20 options:a) 70.56 feet183.38 feet b) 92.75 feet310.59 feet c) 92.75 feet183.38 feet d) 70.56 feet314.74 feet e)
Physics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

C is the correct answer

Explanation:

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An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g
9966 [12]

The astronaut will take 300 seconds

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum of the astronaut+object system must be conserved.

Initially, they are both at rest, so their total momentum is zero:

p=0

After the astronaut throws the object, their total momentum is:

p=MV+mv

where:

M = 80 kg is the mass of the astronaut

V is the final velocity of the astronaut

m = 500 g = 0.5 kg is the mass of the object

v = 8.0 m/s is the velocity of the object

Since momentum is conserved, we can write

0=MV+mv

And solving for V,

V=-\frac{mv}{M}=-\frac{(0.5)(8.0)}{80}=-0.05 m/s

Which means that he starts moving at 0.05 m/s in the direction opposite to the object.

Now the astronaut needs to cover a distance of

d = 15.0 m

And his speed is

v = 0.05 m/s

Therefore, the time taken is

t=\frac{d}{v}=\frac{15.0}{0.05}=300 s

Learn more about momentum here:

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3 0
4 years ago
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.245 T. If the kinetic energy of the electr
Amiraneli [1.4K]

Answer

Given,

Magnetic field, B = 0.245 T

KE of the electron = 2.90 x 10⁻¹⁹ J

Speed of electron = ?

KE = \dfrac{mv^2}{2}

v=\sqrt{\dfrac{2(KE)}{m}}

v=\sqrt{\dfrac{2\times 2.90\times 10^{-19}}{9.11\times 10^{-31}}}

v = 7.97 x 10⁵ m/s

radius of the circular path

so,

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

r=\dfrac{9.11\times 10^{-31}\times 7.97 \times 10^5}{1.6\times 10^{-19}\times 0.245}

r = 1.85 x 10⁻⁵ m

8 0
3 years ago
A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.
Hunter-Best [27]
<span>a solution is a liquid mixture  </span>
4 0
4 years ago
How much heat is needed to raise the temperature of 5g of water by 20oC?
Ratling [72]
Required Heat = Q

Q = Mass * specific heat of water * change in temp.

Q = 5g * 1g/cal*degC * 20degC

Q = 100 cal of heat is required

To convert calories to Joules,
1 cal = 4.184 Joules

100cal = 418.4 J of heat is needed
5 0
3 years ago
If an object floats, the volume of the displaced water is equal to the volume of the portion of the object that's above the surf
diamong [38]

Answer:

FALSE

Explanation:

When object float in water then it means that weight of the object is counterbalanced by the buoyancy force.

Here as we know that buoyancy force is the weight of water displaced by the object.

So here when object is submerged into the water then the submerged part of the volume of object will displace exactly the same volume of water and that volume of water will exert upwards buoyancy force on the object.

So here this statement is not true as it says that volume of water displaced is volume above the surface of water while it must be like volume of water displaced must be equal to volume of submerged part of the object.

4 0
3 years ago
Read 2 more answers
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