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3 years ago

2.5 c = fl oz Cups of water for your thirsty dog and cat

Mathematics

1 answer:

inn [45]3 years ago

7 0

Answer:

20 fluid ounces

Step-by-step explanation:

Each cup contains 8 fl oz. This means that if you multiply 2.5 times 8, you get 20.

If you want to break it down more, you can multiply the 2 * 8, then multiply the .5 * 8. Then add the answers together. So.... you get 16 + 4 = 20 fl oz.

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Find the area of the parallelogram<br><br><br> D1=9<br> D2=15

lutik1710 [3]

Answer:

A=135

Step-by-step explanation:

A=bh

A=(9)(15)

A=135

4 0

3 years ago

Find the volume in fluid ounces of a 5 ml dose of cough syrup (1mL=0.03 oz

natita [175]

Answer

Find out the volume in fluid ounces of a 5 ml dose of cough syrup .

To prove

As given

5 ml dose of cough syrup .

1 ml = 0.03 oz

Now convert 5 ml dose of cough syrup into the ounces .

5 ml dose of cough syrup into the ounces = 5 × 0.03

= 0.15 oz

Therefore the volume of a 5 ml dose of cough syrup in ounces be 0.15 oz .

6 0

3 years ago

Hjhjhjhjhhhhhhhhhhhhhhhjjhkjhjjhhjjkjk

kiruha [24]

Answer:

Step-by-step explanation:

7 0

4 years ago

Which of these relations are functions?

Brums [2.3K]

Answer: None of them are functions.

Step-by-step explanation:

By definition, a relation is a function if and only if each input value have an unique output value.

You need to remember that the input values are the x-values and the output values are the y-values.

In the first table you can observe that the input value 2 has two different output values:

$x=2;y=11\\\\x=2;y=15$

Therefore, this relation is not a function.

Notice that in the second table the input value -4 has two different output values:

$x=-4;y=-2\\\\x=-4;y=-5$

Therefore, this relation is not a function.

In the set $\{(-5,-7), (-2,-7), (7,17), (-5,21)\}$ , observe that the input value -5 has two different output values:

$x=-5;y=-7\\\\x=-5;y=21$

Therefore, this relation is not a function.

3 0

3 years ago

Can anyone explain me?

Alika [10]

Answer:

Step-by-step explanation:

a) (a + b)² = (a + b) * (a +b)

(a + b)³ = (a + b) * (a +b) * (a +b)

a²- b² = (a +b) (a - b)

Here (a + b) is common in all the three expressions

HCF = (a + b)

b) (x - 1) = (x - 1)

x² - 1 = (x - 1) * (x + 1)

(x³ - 1) = (x - 1) (x² + x + 1)

HCF = (x -1)

7 0

3 years ago