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Kazeer [188]
3 years ago
7

Consider the Quadratic function f(x) = 4x^2 - 1. Its vertex is Preview The x value of its largest x-intercept is x = The y value

of the y-intercept is y = Preview Preview Preview

Mathematics
1 answer:
Grace [21]3 years ago
3 0

Answer:

Vertex = (0,-1)

The x value of its largest x-intercept is x=\frac{1}{2}.

The y value of the y-intercept is y = -1.

Step-by-step explanation:

The given function is

f(x)=4x^2-1           .... (1)

The vertex form of a parabola is

g(x)=a(x-h)^2+k         ..... (2)

where, a is a constant, (h,k) is vertex of the parabola.

From (1) and (2) we get

a=4,h=0,k=-1

So, the vertex of the parabola is (0,-1).

Substitute f(x)=0 in equation (1) to find x-intercepts.

0=4x^2-1

Add 1 on both sides.

1=4x^2

Divide both sides by 4.

\frac{1}{4}=x^2

Taking square root both sides.

\pm \sqrt{\frac{1}{4}}=x

\pm \frac{1}{2}=x

The x-intercepts are -\frac{1}{2} and \frac{1}{2}.

Therefore the x value of its largest x-intercept is x=\frac{1}{2}.

Substitute x=0 in equation (1) to find the y-intercept.

f(0)=4(0)^2-1=-1

Therefore the y value of the y-intercept is y = -1.

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