Question

Which point is collinear with points a and d

Answer 1

B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

[4 - (-4)] / (-3 - 3)
(8) / (-6)

The slope of the line is -8/6 or -4/3 simplified

Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x

Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
-8 = -8

So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D

~~hope this helps~~