Step-by-step explanation:
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Y=11x/20 +.25
<span>Solve for </span><span>y</span><span> by </span>simplifying<span> both sides of the </span>equation<span>, then isolating the </span>variable<span>.</span>
Given:
Composite figure.
The figure splitted into two shapes.
One is vertical cuboid and other is horizontal cuboid
To find:
Total surface area of the figure
Solution:
<u>Vertical cuboid:</u>
Length = 14 inches
Width = 12 inches
Height = 24 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 12 + 12 × 24 + 14 × 24)
= 2(168 + 288 + 336)
Surface area = 1584 square inches
<u>Horizontal cuboid:</u>
Length = 14 inches
Width = 10 inches
Height = 30 - 12 = 18 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 10 + 10 × 18 + 14 × 18)
= 2(140 + 180 + 252)
Surface area = 1144 square inches
Total surface area = 1584 + 1144
= 2728 square inches
The total surface area of the figure is 2728 square inches.
There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
ex: x^2+ 4x + 3 =0
(x+3) (x+1) = 0
x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)
2) The other way to solve a quadratic function is by using a formula:
given: ax^2 +bx +c=0
x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
ex: 3x^2 + 4x -2=0
x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
and
x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
Answer:
B)
Step-by-step explanation:
A function is when every input has one output.
Easiest way is to do the "vertical line test" and "horizonal line test."
Basically you draw a vertical line and a horizontal line.
If either line passes through more than one point, then it is not a function.
The only one that passes them is B, the line.
