Answer:
40
Step-by-step explanation:
8 - 72
x - 360

Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
The last two.
They are equivalent
3+3=6 6•4=24
4•3=12 12+12 is 24
Answer:
<h2>
66 different ways </h2>
Step-by-step explanation:
This is a combination question. Combination has to do with selection. For example if r objects are to be selected from n pool of oblects, this can be done in nCr number of ways.
nCr = n!/(n-r)r!
According to the question, if a radio show can only play 10 records out of 12 records available, this can be done in 12C10 number of ways.
12C10 = 12!/(12-10)!10!
= 12!/2!10!
= 12*11*10!/2*10!
= 12*11/2
= 6*11
= 66 different ways
Answer:
= - 3
Step-by-step explanation:
There is a common ratio between consecutive terms of the sequence, that is
r = 9 ÷ - 3 = - 27 ÷ 9 = 81 ÷ - 27 = - 243 ÷ 81 = - 3
The recursive formula is of the form
= r
= - 3