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Hitman42 [59]
3 years ago
15

Average Monthly Temperature Month Temperature January 45 degrees February 42 degrees March 54 degrees April 62 degrees May 78 de

grees June 85 degrees July 92 degrees August 94 degrees September 89 degrees October 78 degrees November 65 degrees December 54 degrees The average monthly temperatures for the city of Mathville are given in the chart above. One year, January's average temperature was 7 degrees warmer, February's was 3 degrees cooler, June's was 2 degrees cooler, August's was 3 degrees warmer, and November's was 7 degrees warmer. What did this do to the average yearly temperature? A) The average remained the same. B) The average increased by 1°. C) The average decreased by 1°. D) The average increased by 17°.
Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

From what I understand the answer is B

Step-by-step explanation:

calculate the difference between the averages that we're dated from each month them look between your answers and from there calculate till you can an answer that fits for each one. The correct one being B

x is the average yearly temperature so another way to work this out as add all of the averages up and then work through by diving each average by twelve them look at the difference between the two

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HELP people say this is easy pleaseeeeee
DaniilM [7]

Answer:

45   80

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. In a game, if you roll a 2 or a 3 on a 6-sided number cube, you lose a turn. NOTE: This is just using one number cube.
Evgen [1.6K]

Answer:

1/3

Step-by-step explanation:

On a 6-sided number cube, the probability that you roll a 2 is 1/6,

(Remember that the probability equals: Number of positive outcomes/ number of possible outcomes) So you have 1 positive outcome (to roll a 2) among 6 possible outcomes.

This same thinking applies for the case of rolling a 3 and the probability is 1/6.

Now you want to roll either a 2 or 3. In probability, when we get an "or" this means that we have to sum up our probabilities.

Thus, the P(2 or 3) = P(2)+P(3)= \frac{1}{6}+ \frac{1}{6}  =\frac{2}{6}=\frac{1}{3}

Thus the probability of rolling a 2 or 3 is 1/3

4 0
4 years ago
The length of a rectangle is 8 cm longer than its width. find the dimensions of the rectangle if its area is 108cm
hram777 [196]

Answer:

4+2\sqrt{31}\text{ by } -4+2\sqrt{31}

Or about 15.136 centimeters by 7.136 centimeters.

Step-by-step explanation:

Recall that the area of a rectangle is given by:

\displaystyle A = w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length is 8 centimeters longer than the width. In other words:

\ell = w+8

And we are also given that the total area is 108 square centimeters.

Thus, substitute:

(108)=w(w+8)

Solve for <em>w</em>. Distribute:

w^2+8w=108

Subtract 108 from both sides:

w^2+8w-108=0

Since the equation is not factorable, we can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 8, and <em>c</em> = -108. Substitute and evaluate:

\displaystyle \begin{aligned} w&= \frac{-(8)\pm\sqrt{(8)^2-4(1)(-108)}}{2(1)} \\ \\ &=\frac{-8\pm\sqrt{496}}{2}\\ \\ &=\frac{-8\pm4\sqrt{31}}{2} \\ \\ &=-4 \pm 2\sqrt{31} \end{aligned}

So, our two solutions are:

w=-4+2\sqrt{31} \approx 7.136 \text{ or } w=-4-2\sqrt{31}\approx -15.136

Since width cannot be negative, we can eliminate the second solution.

And since the length is eight centimeters longer than the width, the length is:

\ell =(-4+2\sqrt{31})+8=4+2\sqrt{31}\approx 15.136

So, the dimensions of the rectangle are about 15.136 cm by 7.136 cm.

5 0
3 years ago
Can someone help me with this problem?
lidiya [134]
Im pretty sure it’s C
3 0
3 years ago
6a-4(2a+3)<br><br> what is the answer<br><br> HELP Thank you
hjlf

Answer:

\huge\boxed{\bf\:2 (-a - 6)}

Step-by-step explanation:

6a - 4(2a + 3)\\6a - (4*2a + 4*3)\\6a - (8a + 12)\\6a - 8a - 12\\- 2a - 12\\\boxed{\bf\:2 (-a - 6)}

Steps:

  • Factorise the second term as the first is already in its simplified form.
  • Solve the first term and the second term by doing the required arithmetic operations.
  • Take the common factor out.
  • The result will be : 2 (- a - 6).

\rule{150pt}{2pt}

3 0
2 years ago
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