Answer:
6 matches
Step-by-step explanation:
Let’s call the teams A B C D
A will play B C D = 3 matches
B will play only C and D as it already played A, making 2 matches
C will play D, making 1 match
D has already played all
Total number of matches is thus 3 + 2 + 1 = 6 matches
Since BC is the hypotenuse...
α = 12
c = 13
Hence..
13² = 12² + ß²
ß = √(13² - 12²)
= √(169 - 144)
= √25
= 5
Hence, AB = 5
I hope this helps!
Answer:
21/20
Step-by-step explanation:
Answer:
x^3-8
Step-by-step explanation:
x^3+2x^2+4x + -2x^2-4x-8
+2x^2 and -2x^2 cancel out
+4x and -4x cancel out
F(x) = |2x-1|-5
f(x) = |2*(x)-1|-5
f(-3) = |2*(-3)-1|-5 ... replace every x with -3
f(-3) = |-6-1|-5
f(-3) = |-7|-5
f(-3) = 7-5
f(-3) = 2 which is the final answer
Side Note: the vertical bars mean "absolute value" which represents distance. Negative distance makes no sense which is why absolute value results are never negative.
