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3 years ago

Can you help me find the value of x and y. I am very confused.

Mathematics

1 answer:

Monica [59]3 years ago

8 0

Hello,
Let's assume top left corner: A
top right corner : B
Bottom right corner: C
Bottom left corner :D

M= middle of [CD]

ABM is a triangle rectangular isocel:

(3√2)²+(3√2)²=y²
==>y²=2*9*2
==>y²=36
==>y=6

The triangle BCM is rectangular with MB=3√2, MC=y/2=3
x²+3²=(3√2)²
==>x²=9*2-9
==>x²=9
==>x=3

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<h2>Explanation:</h2>

In this exercise, we have the following functions:

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First expression:

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Second expression:

$(r\cdot s)(x)$

That is, we get the product of s(x) and r(x):

$(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}$

Third expression:

Here we need to evaluate:

$(r+s)(-2)$

First of all, we find the sum of functions r(x) and s(x):

$(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1$

Finally, substituting x = -2:

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<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

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