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mina [271]
3 years ago
13

ABCD is a parallelogram. Find the measure of ZABC. HELPPP

Mathematics
1 answer:
Lena [83]3 years ago
6 0

Answer:

50°

Step-by-step explanation:

Opposite angels of a parallelogram are congruent to each other.

This means:

<ADC = <ABC

<ADC = 38° + 12°

<ADC = 50°

Since <ADC = <ABC, therefore,

<ABC = 50°

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Answer:

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or -8xy-5=b

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3 years ago
Which of the following number sentences is true?<br> A -9=9<br> B-9=-(9)<br> C 9=(-9)<br> D 9=-(-9)
kondaur [170]

Answer:

A and D are the true number sentences

3 0
3 years ago
This is my last question by the way
Leni [432]

Part A:

There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5

There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75

Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75

So part A answer is <em><u>112.75 (or 112¾)</u></em>

Part B:

We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.

137.5÷24.75=5.55

So the answer to part B is <u><em>5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.</em></u>

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Sorry if it's wrong lol

8 0
3 years ago
I need major help pleaseeeeeeeeeeeeee
sveta [45]
Just make a triangle and an X and Y axis and reflect it over the Y axis.  It's that simple.  Then tell how you did it.  Obviously it will be a reflection.  Name the points (before and after) and you are done.

-Twix
4 0
3 years ago
Best explained and correct answer gets brainliest.
Zolol [24]
Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?

You use the formula ab^x
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x is always the length of time

Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.


Y=4800(1.02)^20
Y=$7132.55

3 0
3 years ago
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