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4 years ago

What is −58+34 any one know?

Mathematics

2 answers:

gavmur [86]4 years ago

7 0

Answer:

-24

Step-by-step explanation:

Ratling [72]4 years ago

7 0

Answer:

-58 + 34 = -24

Step-by-step explanation:

You know what a number line looks like right? Well, you also know that the negative numbers are to the left of the middle of the line at point 0, and the positives are to the right of 0? So, -58 + 34, you would start at -58 and start counting (adding) 34. You do this by "subtracting" a positive 34 from the negative 58, so basically, you could just ignore the negative sign for now and just subtract the problem like this: 58 - 34 = 24. Since 34 is not greater than 58 and you have not "crossed" the middle (0) to get over to the positive side, the answer is still a negative number as your final answer. So, the answer is -58 + 34 = -24.

REMEMBER: On a number line, when you have a negative number and you have to add, you move to the right, or up (if you are doing a vertical line). When you are subtracting on a number line, you move left, or down (if you are doing a vertical line). P.S. I am using the number line example because this is how I add and/or subtract positives and negatives when I don't have a calculator at hand to give the me the answer.

Hope that was helpful and not confusing!!!

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3 years ago

Part 1: Create a scenario for an arithmetic sequence. For example, Jasmine practices the piano for ______ minutes on Monday. Eve

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Let $a_n$ be the n'th term of a sequence,

for example $a_1$ is the first term, $a_2$ is the second term and so on.
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a sequence is arithmetic if the difference between any 2 terms is equal:

so an arithmetic sequence, for the first term = t, and the common difference = d, has the following form:

$a_1=t$

$a_2=t+d$

$a_3=t+d+d$

$a_4=t+d+d+d$

so clearly $a_n=t+d*(n-1)$
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A sequence is geometric, if the ratio between any 2 consecutive terms is the same, and it is called the common ratio.

a geometric ratio with first term = t, and common ratio = r is:

$a_1=t$

$a_2=t*r$

$a_3=t*r*r$

$a_4=t*r*r*r$

thus clearly $a_n=t* r^{n-1}$
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Part 1:

"Jasmine practices the piano for __30___ minutes on Monday. Every day she ____increases_______ her practice time by ____5 minutes_____. "

let $a_n$ be the number of hours Jasmine practices the n'th day,

for n=7, t=30, d=5 we have

$a_7=30+5*(7-1)=30+5*6=30+30=60$ ,

minutes is the time Jasmine practices on the 7the day.

Part 2

"Anthony goes to the gym for ___60___ minutes on Monday. Every day he ___increases______his gym time by ____1/10_of the previous day_____. "

if $S_n$ represents the minutes that Anthony goes to gym on the n'th day,

then

$S_1=60$

$S_2=60+1/10*60=10/10*60+1/10*60=11/10*60=1.1*60$

$S_3=1.1*1.1*60$

$S_4=1.1*1.1*1.1*60$

$S_5=1.1*1.1*1.1*1.1*60= (1.1)^{4}*60= 1.4641*60=87.85$
(minutes)

Part 3: it is clear that the formula that can be derived in Part 2 is:

$S_n=60*(1.1)^{n-1}$

so assume we want to find how many hours does Anthony spend in the gym on the 10th day,

then we calculate $S_10=60*(1.1)^{9}=60*2.358=141.5$ (minutes)

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3 years ago

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Answer:

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Step-by-step explanation:

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