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UNO [17]
3 years ago
6

How to change a quadratic equation into intercept form?

Mathematics
1 answer:
rewona [7]3 years ago
5 0
While most of the ways to write the quadratic equation are redundant and useless, there are three forms that actually have unique uses. These three main forms that we graph parabolas from are called standard form, intercept form and vertex form.

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How to solve for X and Y
vova2212 [387]

60+30

=90 ..180-90=90 use paythagorus fomular tan=opposite over adjacent

5 0
3 years ago
Help me with the questions in the image
aliya0001 [1]

Answer:

12

96

9

38

25

Step-by-step explanation:

<h3>i.a+7 for a=5</h3>

5+7=12

<h3>ii.8(c+3) for c =9</h3>

8(9+3)

8(12)

96

<h3>iii.n+8 divided by 4 for n=28</h3>

=28+8 divided by 4

=36 divided by 4

=9

<h3>iv.6p+40 divided by 5 for p =5</h3>

=6×5+40 divided by 5

=30+40 divided by 5

=70 divided by 5

=38

<h3>v.3x+7 for x=6</h3>

=3×6+7

=18+7

=25

5 0
3 years ago
15+2.5(2x+4)<br> PLease help!
RoseWind [281]

Answer:

Step-by-step explanation:

5x+25

8 0
4 years ago
The difference between teenage female and male depression rates estimated from two samples is 0.07. The estimated standard error
KATRIN_1 [288]

Answer:

The 95%  confidence interval is  0.0112 <  \mu_m - \mu_f < 0.1288

Step-by-step explanation:

From  the question we are told that  

      The  sample  mean difference is  \= x_m - \= x_f  =  0.07

       The  standard error  is  SE  =  0.03

Given that the confidence interval is  95% then the level of significance is mathematically evaluated as

               \alpha  =  100 -  95

               \alpha = 5\%

               \alpha =0.05

Next  we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

         E =  Z_{\frac{ \alpha }{2} } *  SE

substituting values

         E =  1.96 *  0.03

         E =  0.0588

The 95% confidence interval  is mathematically represented as

      (\= x_m - \= x_f  ) - E  <  \mu_m - \mu_f

substituting values

     0.07 - 0.0588  <  \mu_m - \mu_f

    0.0112 <  \mu_m - \mu_f < 0.1288

     

3 0
3 years ago
The value of 7mn to the 2power, for m = 3 and n = -2
siniylev [52]
You mean (7mn)^2, if so...

(7*3*-2)^2

-42^2=1764
5 0
3 years ago
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