Answer:
y = cot(x - ⅓π) + 2
Step-by-step explanation:
The general equation for a cotangent function with the given properties is
y = Acot(Bx + C) + D, where
A = the stretching factor
π/|B| = the period
C = the phase shift (negative is to the right)
D = the vertical shift
A = 1
π/|B| = π, so1/|B| = 1 and B = 1
C = -⅓π
D = 2
The function is
y = cot(x - ⅓π) + 2
The figure below shows the graph of the function with the given parameters.
Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.
It’s either B or C if it’s being translated to the right it’s B but if it’s being translated to the left it’s C
(x-1)^2-4
If u put the vertex into vertex form you get this answer.
Answer:
4
Step-by-step explanation:
substitute: (4)^2 - (8 + 3)
16 - 11 = 4