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3 years ago

Solve for B. R = x(A + B) A) B = (R - A)/x B) B = (A - Rx)/x C) B = (R - Ax)/x

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

3 0

R = x(A+B)

distribute

R=Ax+Bx

subtract Ax from each side

R-Ax=Bx

divideby x

(R-Ax)/x =B

Choice C

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Answer: The simple interest will offer more money.

Step-by-step explanation:

Considering the simple interest offer, we would apply the formula for determining simple interest is expressed as

I = PRT/100

Where

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T represents the duration in years.

From the information given,

P = $1200

R = 0.12 = 0.12 × 100 = 12%

T = 3 years

I = (1200 × 12 × 3)/100 = $432

Total balance after 3 years is

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Considering the compound interest offer, we would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

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n represents the periodic interval at which it was compounded.

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From the information given,

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Therefore,

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3 years ago

For an investment of $26,245, a quarterly statement reports that the account balance is $26,292. The statement also reports that

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For an investment of $26,245, a quarterly statement reports that the account balance is $26,292. The statement also reports that for the same quarter, the rate of return on the investment was - 0.02%. Given the information regarding the investment's quarterly activity, is the reported rate of return reasonable? No the rate should be 3.00%

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3 years ago

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive. He wants each bag to

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Answer:

See explanation

Step-by-step explanation:

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.

Factor number 24 and 60:

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Find the greatest common factor

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Hence, the greatest number of bags William can make is 12.

Each of these bags will have $24\div 12=2$ cans of fruit and $60\div 12=5$ cans of vegetables.

If he made fewer bags, 6 bags, each of these bags will have $24\div 6=4$ cans of fruit and $60\div 6=10$ cans of vegetables.

If he made fewer bags, 4 bags, each of these bags will have $24\div 4=6$ cans of fruit and $60\div 4=15$ cans of vegetables.

If he made fewer bags, 3 bags, each of these bags will have $24\div 3=8$ cans of fruit and $60\div 3=20$ cans of vegetables.

If he made fewer bags, 2 bags, each of these bags will have $24\div 2=12$ cans of fruit and $60\div 2=30$ cans of vegetables.

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