Answer:
<u><em>A black guinea pig crossed with an albino guinea pig producing 12 black offspring</em></u>
b b
B Bb Bb
B Bb Bb
The genotype of the black gunea pig will be BB in this situation and the genotype for the albino pig would be bb.
The gametes formed will be B, B,b, b.
The offsprings will have genotype Bb. They will be heterozygous black.
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<u><em>When the albino was crossed with a second black one, 7 blacks and 5 albinos were obtained</em></u>
b b
B Bb Bb
b bb bb
The genotype of the black parent will be heterozygous i.e Bb in this condition. The genotype of the albino parent will be bb.
The gametes formed will be B,b,b,b.
50% of the offsprings will have the probability of having heterozygous Bb genotype. 50% of the offsprings will have the probability of having albino bb genotype.
It’s fermentation.
Hope this helps and good luck :)
Answer:
nelly will be more scared becacause she has just woke up
Answer:
The G-T mismatches generally originate because of the spontaneous deamination of 5-methylcytosine to thymine. Therefore, correcting G-T to G≡C most probably preserves the original sequence.
In the DNA, the 5-methylcytosine usually goes through the process of deamination to thymine. This transformation may cause a G-T base pair or mismatch of nucleotide pairs. Generally, the mutation like C-T transition is common. The G-T base pair is identified by base excision repair proteins, which withdraws this mismatched base pair.
The repair system encourages methylation of cytosine as the mechanism of the regulation of transcription, which permits the turning off or on the process of transcription on the basis of the requirement of the cells. This also assists in preventing the mutation of DNA.
If it is Not 3-4 Then it should be 2-1!
