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tatiyna
3 years ago
12

C(n) =-9/2 (-4/3) n-1 What is the 2 term in the sequence?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

c(2)=6

Step-by-step explanation:

The explicit formula for the sequence is:

c(n) =  -  \frac{9}{2} ( { -  \frac{4}{3} })^{n - 1}

To find the 2nd term, we substitute n=2 to get:

c(2) =  -  \frac{9}{2} ( { -  \frac{4}{3} })^{2- 1}

We simplify to obtain:

c(2) =  -  \frac{9}{2} ( { -  \frac{4}{3} })^{1}

This is the same as:

c(2) =  -  \frac{9}{2} ( { -  \frac{4}{3} })

We cancel common factors to get:

c(2) = 3 \times 2 = 6

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If you have a number x then the consecutive number is x+1
the multiplication of two consecutive numbers can then be written as x*(x+1)=...
if you find an integer solution for this equation you can write the number as two consecutive integers multiplied with each other, if not you found the exception you are looking for
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x(x+1)=9900
x²+x=9900
-> complete square
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(x+(1/2))²=9900+(1/4)
x+(1/2)=sqrt(9900+(1/4))
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