A.
For this case, let us set the variables:
s = 0 (final destination on the ground)
t = unknown
vo = 0
so = 8000 ft
Using the equation, we calculate for t:
0 = -16 t^2 + 0t + 8000
t = 22.36 s
B.
For this case:
s = unknown
t = 22.36 s
vo = 600 miles/hr = 880 ft/s
so = 0
Using the equation, we calculate for s:
s = -16*(22.36)^2 + 880*22.36 + 0
s = 11, 677.29 ft = 2.21 miles
The answer is right above me yw lol
How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
To solve the question, we need to know the volume of a sphere
<h3>
Volume of a sphere</h3>
The volume of a sphere V = 4πr³/3 where r = radius of sphere.
<h3>How fast the volume of the sphere is changing</h3>
To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.
So, dV/dt = d(4πr³/3)/dt
= d(4πr³/3)/dr × dr/dt
= 4πr²dr/dt where
- dr/dt = rate of change of radius of sphere and
- 4πr² = surface area of sphere
Given that
- dr/dt = + 3 cm/s (positive since it is increasing) and
- 4πr² = surface area of sphere = 10 cm²,
Substituting the values of the variables into the equation, we have
dV/dt = 4πr²dr/dt
dV/dt = 10 cm² × 3 cm/s
dV/dt = 30 cm³/s
So, how fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.
Learn more about how fast volume of sphere is changing here:
brainly.com/question/25814490
The values of y get closer to the axis...
The item has 42/140 * 100,or 30% of its initial value. That means that it lost 70% of its value, so 70% is the percent decrease.
