Answer:
78 ????? I can't find a logic or math error take the answer for what is worth
Step-by-step explanation:
Check my work for yourself and post your answer.
Extend the long diagonal to the point (6,4) to create a large triangle that has a base of 14 and a height 12 so this super triangle area is
area = 1/2 bh
= 1/2 (14)(12)
= 7(12)
= 84 sq units
Now subtract off two smaller triangles that were created when the diagonal was extended to the (6, 4) point
area1 = 1/2 bh
= 1/2 (4)(2)
= 4 sq units
area2 = 1/2 bh
= 1/2 (2)(2)
= 2 sq units
Total area = area - area1 - area2
= 84 - 4 - 2
= 78 sq units
Answer:
Step-by-step explanation:
You cannot add these because they are not like. IF you have a value for x, then the expression could be evaluated at the x value, but you can't add them.
1. If the total baggage fees were equal, you would have to equate the two situations. Suppose x is the weight above the limit on the flight home, while y is the weight above the limit on the flight back to college. Then, the equation would be:
20 + 8x = 26 + 5y
Now, we have two unknowns, but only one independent equation. This is unsolvable unless we make an assumption. Suppose the excess weight for both trips are the same such that x=y, then,
<em>20 + 8x = 26 + 5x</em>
2. Then, we solve for x.
8x - 5x = 26 - 20
3x = 6
x = 6/3 = <em>2 lb</em>
Thus, Elizabeth's bag was 2 lb over the weight limit.
3. The total baggage fee would then be:
20+8(2) = 26 + 5(2) = <em>$36</em>
Answer:
m = -18
Step-by-step explanation:
-34=m-16
+16. +16
-18 = m