All categories

3 years ago

Please answer this math question !! 20 POINTS AND BRAINLIEST!!

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

Answer:

3.1 ≤d≤183.1

Step-by-step explanation:

d = 4.5t + 3.1

Since this is a line, we can find the range by putting in the minimum and maximum of the domain

domain = 0≤t≤40

Let t =0

d = 0+3.1 so the minimum of the range is 3.1

Let t = 40

d = 4.5(40)+3.1

d = 183.1 so the maximum is 183.1

The range is 3.1 ≤d≤183.1

You might be interested in

Find the value of c in parallelogram RSTU.

fenix001 [56]

Answer: i believe the answer is c=37. explanation: the two lengths are equal so if one side equals 2c and the other is c+37 then c+37 is just c+c making c equal to 37

5 0

3 years ago

-5x+7y=-34<br> -5x+3y=-6

lisov135 [29]

Answer:

Step-by-step explanation:

-5x + 7y = -34 ⇒ -5x = -34 - 7y

-5x + 3y = -6

-34 - 7y + 3y = -6

-34 - 4y = -6 {add 34 to both sides}

-4y = 28 {divide both sides by (-4)}

y = - 7

-5x + 3y = -6

-5x + 3(-7) = -6

-5x - 21 = -6 {add 21 to both sides}

-5x = 15 {divide both sides by (-5)}

x = -3

7 0

2 years ago

Balloon A is charged, and balloon C is charged. If balloon A approaches balloon C, there’ll be a force of between them.

ipn [44]

Answer:

Step-by-step explanation:im not good at long answers but it should push each other away.

5 0

3 years ago

a triangle is placed in a semicircle with a radius of 7cm, as shown below. find the area of the shaded region. use the value 3.1

makvit [3.9K]

Answer:

27.93mm^2

Step-by-step explanation:

3 0

3 years ago

A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)

Maksim231197 [3]

Answer:

The 95% confidence interval is $0.0503 < p < 0.1297$

The sample proportion is $\r p = 0.09$

The critical value is $Z_{\frac{\alpha }{2} } = 1.96$

The standard error is $SE =0.020$

Step-by-step explanation:

From the question we are told that

The sample size is n = 200

The number of defective is k = 18

The null hypothesis is $H_o : p = 0.08$

The alternative hypothesis is $H_a : p > 0.08$

Generally the sample proportion is mathematically evaluated as

$\r p = \frac{18}{200}$

$\r p = 0.09$

Given that the confidence level is 95% then the level of significance is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the standard of error is mathematically represented as

$SE = \sqrt{\frac{\r p (1 - \r p)}{n} }$

substituting values

$SE = \sqrt{\frac{0.09 (1 - 0.09)}{200} }$

$SE =0.020$

The margin of error is

$E = Z_{\frac{ \alpha }{2} } * SE$

=> $E = 1.96 * 0.020$

=> $E = 0.0397$

The 95% confidence interval is mathematically represented as

$\r p - E < \mu < p < \r p + E$

=> $0.09 - 0.0397 < \mu < p < 0.09 + 0.0397$

=> $0.0503 < p < 0.1297$

7 0

3 years ago