The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).
Therefore, 
t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :
= 0.020908803
The p value is 0.0209
So we reject the null hypothesis and conclude that 
Answer:
y= -1.5x-7 is the equation of the perpendicular line
Here's why:
when we convert 2x-3y=8 to standard form, we get y= 2/3x-8/3. This means the perpendicular line will have a slope of the negative reciprocal of the original one, so the perpendicular slope is -1.5. When we substitute the points (-2,-4) into the equation y=-1.5x+b, we get a b value of -7. So the perpendicular line equation is y= -1.5x-7. You can't the parallel line equation with the points (-2,-4) as it is part of the line 2x-3y=8.
Answer:
<em>The answer is 1.2001 * 10^-5</em>
the answer is 134 and the Remainder is 19
