Answer:
2 5/8 to 1.
Step-by-step explanation:
That would be 1 3/4 divided by 2/3.
= 7/4 / 2/3
= 7/4 * 3/2
= 21 / 8
= 2 5/8
Answer 2 5/8 to 1.
The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:
![\mathbf{h(t) = -16t^2 + 160t}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%28t%29%20%3D%20-16t%5E2%20%2B%20160t%7D)
Differentiate the function with respect to t
![\mathbf{h'(t) = -32t + 160}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%27%28t%29%20%3D%20-32t%20%2B%20160%7D)
Set to 0
![\mathbf{h'(t) = -32t + 160 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7Bh%27%28t%29%20%3D%20-32t%20%2B%20160%20%3D%200%7D)
So, we have:
![\mathbf{-32t + 160 = 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%2B%20160%20%3D%200%7D)
Collect like terms
![\mathbf{-32t =- 160 + 0}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%3D-%20160%20%2B%200%7D)
![\mathbf{-32t =- 160}](https://tex.z-dn.net/?f=%5Cmathbf%7B-32t%20%3D-%20160%7D)
Solve for t
![\mathbf{t = \frac{- 160}{-32}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bt%20%3D%20%5Cfrac%7B-%20160%7D%7B-32%7D%7D)
![\mathbf{t = 5}](https://tex.z-dn.net/?f=%5Cmathbf%7Bt%20%3D%205%7D)
Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
Answer:
200
Step-by-step explanation:
160/80 is 2. 2 times 100 is 200
Answer:
it's a
Step-by-step explanation:
just took the testttt