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Bad White [126]
3 years ago
8

Draw an array for the equation 5+5+5=15

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0
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I'm not for sure if this is what you meant though sorry
You might be interested in
|5x-4|>16 solutions
lions [1.4K]

Answer:

x >4                         or            x < -12/5

Step-by-step explanation:

An absolute value has 2 solutions, a positive and a negative.  Remember to flip the inequality for the negative solution

|5x-4|>16

5x-4 > 16        5x-4 < -16

Add 4 to each side

5x-4 +4> 16+4   or     5x-4+4 < -16+4

5x > 20                or        5x < -12

Divide each side by 5

5x/5 > 20/5          or         5x/5 < -12/5

x >4                         or            x < -12/5

5 0
2 years ago
Need help ace<br><br> help pls
Alexandra [31]

Answer:

Hello I am an ace! answer: 8

Step-by-step explanation:

Volume for a cube is just length × width × height so you only need to know 1 for a cube because they will all be the same number so 8 is the answer because 8 × 8 × 8 = 512 Hope this helps!

8 0
2 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
The values shown represent the y-values that correspond to x-values from x = 1 through x = 5.
rjkz [21]
The answer is B because every number is adding up to 6
7 0
2 years ago
Explain how you would find the height of a rectangular prism if you know the volume is 60 centimeters and that the area of the b
ZanzabumX [31]
U have to add 60+10 then 60-10=50+20=70 and that is the answer that u u get addition subtraction those are the only to that u use.
4 0
3 years ago
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