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3 years ago

Help!!! Two customers took out car loans from a bank.

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

Answer:

Susan paid $2220 more

Step-by-step explanation:

Use the interest formula:

I = Prt, where P - amount of loan, r- interest rate, t- time in years

Robert:

I = 30000*(4.9/100)*4 = 5880

Susan:

I = 30000*(4.5/100)*6 = 8100

Difference in amounts of interest:

8100 - 5880 = 2220

Susan paid $2220 more

Sphinxa [80]3 years ago

3 0

Answer:

$2220

Step-by-step explanation:

I took the test and made a 100%

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Please help write the equation of the line.

AfilCa [17]

Answer:

x -2y -2=0

Step-by-step explanation:

using the formula, m= ( Y2 - Y1)/( X2-X1)

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the equation of the line is obtained using the formula

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3 years ago

Which of the following values is a solution of |2-x| less than 4

morpeh [17]

The correct answer is -1.

In order to solve this, we need to split into the positive and negative version of the answers. Let's start with the positive version.

2 - x < 4

-x < 2

x > -2 ----> NOTE: When we divide by -1, we have to change the direction of the sign.

Now we'll do the negative version.

2 - x > -4

-x > -6

x < 6

So we know the number must be greater than -2, but less than 6. The only number on this list that fits that is -1.

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3 years ago

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

exis [7]

Answer:

Step-by-step explanation:

the length of the hypotenuse is 4 Km, it is probable that you are looking for the value of the cathetus a.

it is a right triangle and we use Pythagoras

a² = 4² - 2²

a² = 16 - 4

a² = 12

a = √12

a = 3.46 (round 3.5)

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2 years ago

Grayson is deciding between two truck rental companies. Company A charges an

777dan777 [17]

GRAYSOJN FARTED AND TRHENNXSU23RF EFKL'

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3 years ago

Find the missing lengths: LO=5 and OK=4, find OH and KH.

hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.

In ΔLOH

By Pythagoras theorem

$LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2$ → (1)

In ΔKOH,

$KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2$ → (2)

In ΔKHL,

$KL^2=LH^2+KH^2$

Using eq (1) and (2), we get

$KL^2=5^2+OH^2+OH^2+4^2$

$9^2=25+2OH^2+16$

⇒ $2OH^2=81-25-16=40$

⇒ $OH=\sqrt{20}=6.324\sim6.3units.$

Put the above value in eq 2, we get

$KH^2=20+4^2=36$

⇒ KH=6 units.

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4 years ago

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