Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
250 girls
Step-by-step explanation:
Please let me know if you want me to write an explanation for my answer :)
Answer: v = u= 
Step-by-step explanation:
v= cos45 * 4=
- Apply Pythagorean theorem
= 
We have u =
You can try then by plotting the points in.
The answer is C
Make sure by plotting in the points, lets take (-5,27)
y = 12 -3(-5)
y = 12 + 15
y = 27
27 = 27
This is correct
Lets try (-1,15)
y = 12 -3(-1)
y = 12 + 3
y = 15
15 = 15
This is correct
Lets try (8,-12)
y = 12 -3(8)
y = 12 - 24
y = -12
-12 = -12
This is correct too.
The correct ordered pairs are <span>C(-5,27),(-1,15),(8,-12)</span>
Answer:
37 hours
Step-by-step explanation:
4.5 + 8.75 + 9.5 + 10 + 4.25 = 37 hours
