All categories

3 years ago

What is an absolute value of an interger

Mathematics

1 answer:

Dominik [7]3 years ago

5 0

Answer:

its the distance it has from 0 on the number line.

Step-by-step explanation:

You might be interested in

What is 17.8 rounded to the nearest tenth

inysia [295]

It would still be 17.8, unless there are more numbers after the 8.

4 0

4 years ago

PLEASE HELP!!<br><br> Solve the equation. Please show your math work step by step. 5x −14=−34

MrMuchimi

Hey

The Answer is -4x

Heres the Step by Step work

You add 14 to each side because it is negative, so

5x-14=-34

+14|+14

and you will end up with

5x=-20

Divide 5 on each side, so

5x=-20

/5x | /5x

-20 / 5x =

x=-4

-4x

mark branliest plz

8 0

3 years ago

Just how much is a million?

Fudgin [204]

Hey You!

1 million = 1,000,000

In other words, 1 million is 1000 1000s.

7 0

3 years ago

Read 2 more answers

#7: Find the surface area of the square pyramid shown below. * 10 IN. 6 IN. 6 IN. SURFACE AREA = IN2

Serhud [2]

360 IN.2?

Step-by-step explanation:

i don't know if correct

nakalimutan kuna yan kung pano gawin sorry

3 0

3 years ago

Read 2 more answers

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

4 years ago