3 years ago

The following stem-and-leaf plot shows scores on a recent literature exam for both Class A and B.

1 answer:

3 0

The mean score is obtain by (sum of scores) ÷ (how many scores there are)

Class A:

Sum of scores = 60 + 68 + 70 + 75 + 84 + 86 + 90 + 91 + 92 + 94 + 94 + 96 + 100 + 100 = 1200

There are 14 scores in total

Mean scores of class A = 1200÷14 = 85.7
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Sum of scores of class B = 60 + 60 + 70 + 71 + 73 + 73 + 75 + 76 + 77 + 84 + 85 + 86 + 91 + 92 = 1073

Number of scores of class B = 14
Mean scores of class B = 1073÷14 = 76.6
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Class A has the highest mean score

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marin [14]

Answer:

$\large\boxed{(h\circ g)(x)=6x-16}$

Step-by-step explanation:

$h(x)=3x-1\\\\g(x)=2x-4\\\\(h\circ g)(x)=h\bigg(g(x)\bigg)\\\\\text{Substitute instead of x the expression (2x - 4) to h (x):}\\\\(h\circ g)(x)=3(2x-4)-4\qquad\text{use the distributive property}\\\\(h\circ g)(x)=(3)(2x)+(3)(-4)-4\\\\(h\circ g)(x)=6x-12-4\\\\(h\circ g)(x)=6x-16$