Answer:
Points J and K could be located at:
J(2,2)
K(6,2)
Step-by-step explanation:
Consider the vertices have a x and y coordinate:
A: x coordinate=-7 y coordinate=-2
B: x coordinate=1 y coordinate=-2
C: x coordinate=1 y coordinate=-8
D: x coordinate=-7 y coordinate=-8
G: x coordinate=2 y coordinate=5
H: x coordinate=6 y coordinate=5
Then it is possible to calculate the distance between the x and y coordinates:
x coordinate of Vertices AB:
x coordinate of B- x coordinate of A=1-(-7)=8
The distance between A and B is 8
y coordinate of Vertices AC:
y coordinate of A- y coordinate of C=-2-(-8)=6
The distance between A and C is 6
Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.
Repeat the analysis with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.
x coordinate of Vertices GH:
x coordinate of H- x coordinate of G=6-(2)=4
The distance between G and H is 4
We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>
Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>
<em />
Points J and K could be located at:
J(2,2)
K(6,2)
converges if 
is monotonic and 
as 
. Here 
.
. Then 
, which is positive for all 
, so 
is monotonically increasing for 
must be a monotonically decreasing sequence over the same interval, and so must 
.